Question

Find the smallest number which when divided by 15, 20 and 25 leaves a remainder

five in each case.​

Answer 1

Answer:

100 ➗ divide the no.15,20and25

Answer 2

Answer:

Step-by-step explanation:

Let m be the number

Then m-5 will be the lcm of 15, 25 and 35

15=3x5

25=5x5

35=5x7

So lcm =3x5x5x7 = 525

So the smallest number which when divided by 15, 25 and 35 leaves a remainder 5 is 530.