Question

find the smallest number which when divided by 15,25,28 leaves the remainder 8 in each case​

Answer 1

Answer:

first we need to find the lowest common multiple of 15,25 and 28 that is 2100.so 2100 is divisivle by each of the three numbers.add 8 to it so that when it is divided by any of the three numbers the remainder comes out to be 8.