Find the smallest number which when divided by 15 25 and 35 leaves a reamandiar 5 in each case
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13
Answer: 530
Step-by-step explanation:
Let m be the number
Then m-5 will be the lcm of 15, 25 and 35
15=3x5
25=5x5
35=5x7
So lcm =3x5x5x7 = 525
So the smallest number which when divided by 15, 25 and 35 leaves a remainder 5 is 530
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2
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