Find the smallest number which when divided by 15and 27respectively, leaves a remainder 7in each case
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Answer:
WE HAVE TO FIND THE LCM OF 15 AND 27 WHICH IS 135
THEN WE HAVE TO ADD 7
SO
135+7
=142
CHECK
142÷15
=QUOTIENT-9
REMAINDER-7
142÷27
=QUOTIENT-5
REMAINDER-7
THANK YOU
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