find the smallest number which when divided by 16,24,32,48 leaves a remainder 13, 21,29 ,45
Options are 98,96,93,8
Answers
Answer:
477 (Your options are wrong)
Explanation:
First , we have to find the number which is least divisible by 16 , 24 , 32 , 48
That is ,
We have to find the Least Common Multiple (L.C.M) of the above numbers
L.C.M of 16 , 24 , 32 and 48 = 480
Therefore , the least number divisible by 16 , 24 , 32 , 48 is 480
Here ,
We can see that the remainder is less by 3 than the corresponding divisors
For example ,
13 is 3 less than 15 ; 21 is 3 less than 24 ; 29 is 3 less than 32 and 45 is 3 less than 48 .
Therefore ,
The number which (if) gets divided by 16 , 24 , 32 and 48 will give a remainder 13 , 21 , 29 and 45 respectively will be ,
L.C.M of 16, 24 , 32 and 48 - 3
480 - 3 = 477
The answer to your question is 477 .
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