Question

find the smallest number which when divided by 16,24,32,48 leaves a remainder 13, 21,29 ,45

Answer 1

At first find the least no. divisible by 16,24,32,48,

  Least no. that is divisible by 16,24,32,48= L.C.M of 16,24,32,48.

    L.C.M of 16,24,32,48 = 480. 

SO the least number divisible by 16,24,32,48 = 480. 

  Now, As we can see that remainder is always 3 less than corresponding divisors.

  i.e 16 - 3 = 13 or 24 - 3 = 21 or 32 - 3 = 29 etc.

 Therefore the number will be 480 - 3 = 477.

ɧơ℘ɛ ıɬ ɧɛƖ℘ʂ☺☺

Answer 2

the correct answer is 477