Question

find the smallest number which when divided by 18,27, and 36 leaves a remainder 5 in each case.

Answer 1

LCM of 18,27,36 = 2 x 2 x 3 x 3 x 3 = 108

Smallest number = 108 + 5 = 113

Answer 2

The smallest number which when divided by 18,27, and 36 leaves a remainder 5 in each case is 113.

Step-by-step explanation:

Given:

Find the smallest number which when divided by 18,27, and 36 leaves a remainder 5 in each case.

Solution:

To find the common number that divides all the given 3 numbers,  

LCM of 18, 27, 36 = $2 \times 2 \times 3 \times 3 \times 3$ = 108

Smallest number that leaves a remainder 5 = 108 + 5 = 113  

Result:

The smallest number which when divided by 18,27, and 36 leaves a remainder 5 in each case is 113.

To know more:

Find the least number which when divided by 6, 15, 18 leave remainder 5 in each case

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