Math, asked by Anonymous, 1 year ago

how to solve biquadratic equation.

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Answered by sahed
0
A quadratic equation is an equation where the highest exponent of a variable is 2. There are three main ways to solve quadratic equations: 1) to factor the quadratic equation if you can do so, 2) to use the quadratic formula, or 3) to complete the square.
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Anonymous: idiot i asked for bi quadratic equation
Answered by SrijanShrivastava
0

We can solve Any Quartic Equation of the form

 \sf f(x) = a {x}^{4}  + b {x}^{3}  + c {x}^{2}  + dx + e

We simply need to solve the resolvent cubic generated by the Quartic equation by completing the square twice.

 \sf8 {a}^{3}  {(z)}^{3}  - 4 {a}^{2} c {(z)}^{2}  + (2abd - 8 {a}^{2} e)(z) + (4ace - a {d}^{2}  -  {b}^{2} e) = 0

Therefore, the Four roots are given by the roots of the Two Quadratic equations:

  \sf{x}^{2}  + ( \frac{b + \sqrt{   {b}^{2} - 4ac + 8 {a}^{2} z }}{2a}   )x + (z +  \sqrt{ {z}^{2}  -  \frac{e}{a} } ) = 0

 \sf {x}^{2}  + ( \frac{b - \sqrt{  {b}^{2} - 4ac  + 8 {a}^{2} z}}{2a}  )x + (z -  \sqrt{ {z}^{2}  -  \frac{e}{a} } ) = 0

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