Find the smallest number which when divided by
18, 27 and 36 leaves a remainder 5 in each case.
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0
Answer:
113 divided by 18 27 and 36 gives a remainder 5.
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2
L.C.M of 18,27&36 is 2*2*3*3*3=108
108+5 =113...
And thus,
113 is the answer
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