simplify:a(a²+a+1)+5 and find value if, (1) a= 0( 2)a= -1
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Answered by
28
a(a^2+a+1)+5
= a^3+a^2+a+5
(1)
Now if a=0 :-
0^3+0^2+0+5 = 0+0+0+5 = 5
In the first case 5 is the answer
(2)
Now if a= (-1^3)+(-1^2)+(-1)+5 = -1+1-1+5 = 4
In the second case 4 is the answer.
Answered by
30
If a=0,then
a(a square+a+1)+5
=0(0+0+1)+5
=0+5
=5
If a=-1,then
a(a square+a+1)+5
=-1(-1+1+1)+5
=1+1+1+5
=8
Anonymous:
your answer is incorrect in second case.
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