Math, asked by anitamarneanita7485, 9 months ago

Find the smallest number which when divided by 21 28 36 and 45 leaves a remainder 3

Answers

Answered by devrajsharma299

1

Step-by-step explanation:

LCM = 2^4 X 7 X 5 (Taking the highest power of the nos.) So 560 Is the smallest number which the above three nos divide

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