Math, asked by Anonymous, 10 months ago

Find the smallest number which when divided by 24,30 and 40 leaves no remainder. Please Do it Fast Cause Its Urjent

Answers

Answered by babysalinisajin
10

Answer:

The smallest no. which when divided by 24, 30 and 40 leaves no remainder is 120.

Step-by-step explanation:

First, find the LCM of 24,30 and 40

2|24,30,40

2|12,15,20

2|6,15,10

3|3,15,5

5|1,5,5

1,1,1

LCM = 2×2×2×3×5 = 120

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