the modules if 5+4i÷1+i
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Answer:
for any complex number x+ iy modules= √(x²+y²)
here complex no. is 3+4i
here X = 5+4i Y = 1+i
thus modules =√{(5+4)²+(i)²} = √(81+0) = √81 = 9
thus modules value for complex no. 5+4i÷1+i = 9
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