find the smallest number which when divided by 24 32 and 36 leaves remainder 5
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Answer:
The smallest number which when divided by 24 ,32 and 36 leaves remainder 5 is = 293
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First take LCM of 24,32,36
LCM would be = 288
then add 5 to 288 to get your desired answer
so, smallest number would be 293
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