Question

find the smallest number which when divided by 24,36and 64 leaving remainder in 4 each case​

Answer 1

Let the unknown number be'x'

 According to the condition of the problem,

x÷24;x÷36 and x÷64 , all leaves a remainder 4  

24 = 2×2×2×3

36 = 2×2×3×3

64 = 2×2×2×2×2×2  

LCM(24,36,64) = 2⁷×3²                          

= 1152  

Hence the answer is (1152+4)

i.e., 1156