Question

find the smallest number which when divided by 24 and 36 and 64 leaving 4 as remainder in each case...

( b ) A number is be divisible by 24 and 25 and 120 is it is increased by 20. find the number ....

c / number is divisible by 16 and 25 and 75 if it is decreased by 10. find the number ​

Answer 1

First, we need to find the LCM of 24, 36 and 48. The LCM of 24, 36 and 48 is 144.

Now, we shall find the difference of 24 and 21 which is 3. Similarly, the difference of 36 and 33 and also that of 48 and 45 is 3 respectively.

The difference between the LCM and 3 is the smallest number.

So, 144 - 3 = 141.

Hence, 141 is the smallest number when divided by 24, 36 and 48 leave remainders 21, 33 and 45 respectively.

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