Question

Find the smallest number which when divided by 25, 45, 55 leaves the remainders 12, 17 and 27
respectively


Please answer it​

Answer 1

Answer:

364

Step-by-step explanation:

a=bq+r

25=bq+12

bq =13

a=bq2+r

45=bq2+17

bq2=28

a=bq3+r

55=bq3+27

bq3=28

then find LCM of 13,28,28

and it is 364.

therefore answer will be 364.

Answer 2

Answer:

mark me as brainliest

Step-by-step explanation:

Given: Find the smallest number which when divided by 18,27, and 36 leaves a remainder 5 in each case. Result: The smallest number which when divided by 18,27, and 36 leaves a remainder 5 in each case is 113.