Question

find the smallest number which when divided by 28 and 32 leaves the same remainder 8 and 12 in each case​

Answer 1

Answer:

28-8=20 & 32-12=20 So the reqd no will be 20 less than the L. C. M. of 28 and 32 . L. C. M. of 28 & 32 is = 224 Reqd smallest no =224-20 = 204.

Answer 2

Answer:

Step-by-step explanation:

Let the number be x

28/x=8

32/x=12

28=8x

x=28/8=7/2

Now let's confirm the answer

32/x=12

12x=32

x=32/12

x is not equal to x, thus the question is wrong