Question

Find the smallest number which when divided by 39,52 and 65, leaves a
remainder of 5 in each case.

Answer 1

Answer:

Okokokokokokokoko MARK AS BRAINLIEST

Answer 2

Answer:

785

Step-by-step explanation:

we hv to find the smallest no which when divided by 65,52, and 39 give s a reminder -5 in each case .

take L.C.M of all three nos

primfactorize

39=3*13

52=2*2*13

65=5*13

LCM of = 2*2*3*5*13=780

required no = 780+5= 785

answer - 785

hope this helps