Question

Find the smallest number which when divided by 42, 35 and 56 leaves no remain
umber
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Answer 1

Answer:

Step-by-step explanation:

5880

Answer 2

Answer:

840

Step-by-step explanation:

The needed number is LCM of 42, 35 & 56.

42 = 2x3x7

35 = 5x7

56 = 2x2x2x7

The LCM is 2x2x2x3x5x7 = 8x5x21 = 40x21 = 840

Thus, the smallest number which when divided by 42, 35 and 56 leaves no remain der is 840.

Hope this helps!