find the smallest number which when divided by 6,7 or 8 will leave remainder 5 in each case.
a) 47 b)173 c)53 d)60
sumithabib:
173
Answers
Answered by
30
It is 173
173/6 gives remainder 5
173/7 gives remainder 5
173/8 gives remainder 5
173/6 gives remainder 5
173/7 gives remainder 5
173/8 gives remainder 5
For this problem this is good enough to understand
LCM is 84
tell me LCM of 6,7,8
LCM of 6,7,8 = 168
TX for the helping hand
173
173
very nice and clean
173
it was easy question
Answered by
35
Prime factorization of 6 = 2 * 3
Prime factorization of 7 = 7
Prime factorization of 8 = 2 * 2 * 2
LCM(6,7,8) = 168.
The smallest number that when divided by 6,7,8 will leave remainder 5 in each case = 168 + 5 = 173.
Therefore the smallest number = 173.
Hope this helps!
Prime factorization of 7 = 7
Prime factorization of 8 = 2 * 2 * 2
LCM(6,7,8) = 168.
The smallest number that when divided by 6,7,8 will leave remainder 5 in each case = 168 + 5 = 173.
Therefore the smallest number = 173.
Hope this helps!
8= 2,2,2
Thanks
TX for the helping hand
it was a easy question
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