find the smallest number which when divided by 8 9 10 15 20 give the remainder 5
Answers
Answered by
54
LCM of 8 = 2^3
LCM of 9 = 3^2
LCM of 10 = 2 * 5
LCM of 15 = 3 * 5
LCM of 20 = 2^2 * 5
LCM of 8,9,10,15,20 = 2^3 * 3^2 * 5
= 360
smallest number = 360 + 5 = 365
Hope this helps!
LCM of 9 = 3^2
LCM of 10 = 2 * 5
LCM of 15 = 3 * 5
LCM of 20 = 2^2 * 5
LCM of 8,9,10,15,20 = 2^3 * 3^2 * 5
= 360
smallest number = 360 + 5 = 365
Hope this helps!
Answered by
16
40 is the answer , I hope so
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