Find the smallest number which when divided by 8,9,10, 15, 20 gives remainder of 5 every time
Answers
Answered by
1
365
Hence, 365 is the smallest number which when divided by 8, 9, 10, 15, 20 gives a remainder of 5 every time.
Similar questions
Art,
27 days ago
Math,
27 days ago
English,
1 month ago
India Languages,
10 months ago
Math,
10 months ago