find the smallest number which when divided by8,9,10,15,20 given a remainder of 5 every time
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no number is there to be divided with these kind of numbers
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Solution by Shivnath Sharma
Here
Fist take LCM
8,9,10,15,20
Then Add 5
See here
2×2×2×3×3×5 = 360
Now add 5
360+5= 365
This number is divided by 8,9,10,15,20
And reminder left 5
Shivnath Sharma
L.P.F
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