Math, asked by kavita237, 11 months ago

find the smallest number which when divided by8,9,10,15,20 given a remainder of 5 every time​

Answers

Answered by harsimrankaur1032
0

Answer:

no number is there to be divided with these kind of numbers

Answered by kumarshivnath790
2

Answer

Solution by Shivnath Sharma

Here

Fist take LCM

8,9,10,15,20

Then Add 5

See here

2×2×2×3×3×5 = 360

Now add 5

360+5= 365

This number is divided by 8,9,10,15,20

And reminder left 5

Shivnath Sharma

L.P.F

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