Math, asked by Priyanshu2422U, 11 months ago

Find the smallest number which when divides 28 and 32, leaving remainders 8 and 12

respectively. ( plese explain why we do minus 20 from the LCM )

Answers

Answered by vasunattevasu515

0

Answer:

28-8,32-8

20,20

LCM of 20,20

LCM =100

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