Question

Find the smallest number which when divides by 15, 20, 25 and 30, leaves 5 as remainder in each case

Answer 1

Answer:

300

Step-by-step explanation:

15-5=10

20-5=15

25-5=20

30-5=25

now LCM of 10 15 20 and 25 will be your answer

5×5×2×2×3=300