find the smallest number which when divisible by 16,18 and 32leaves a remainder 5 in each case
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Firstly , start with finding The LCM of having two number (16 And 18 ) and that is 144 now her , according to the question we need to find a number , which is eight acces to the multiply of 144 and it should also be smallest 4 digit number
required number =144 x + 8 her putting x= 7 we get the required number to be 1016 . if any doubts in understanding the method the lave a comment
required number =144 x + 8 her putting x= 7 we get the required number to be 1016 . if any doubts in understanding the method the lave a comment
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