Physics, asked by justinbiberr, 1 year ago

find the moment of force of 20N about axis of rotation at distance 0.5m from the force

aasusingh: it's answer is 25

aasusingh: moment of force is called torque nd is equal to force ×displacement

aasusingh: so torque =50×0.5 =25

Answers

Answered by aasusingh

this will help u dear

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aasusingh: I hope this will help u...dear

justinbiberr: in book they had given 10nm

aasusingh: na....then may be answer in the book is wrong. ..because it's a very simple answer. so I don't think that mine is wrong

Answered by Anonymous

Find the moment of force of 20N about axis of rotation at distance 0.5m from the force.

We know,

${\underline {\underline {\boxed {\red {\sf {Moment \: of \: force = Force \times ⊥ Distance }}}}}}$

$\sf {☞ \: Moment \:of \:force = F × ⊥ Distance}$

$\sf {☞ \: Moment \: of\: force = 20N × 0.5 m}$

$\sf { ☞ \:Moment \: of \:force = 10 Nm }$

Therefore, the moment of force of 20N about axis of rotation at distance 0.5m from the force is 10Nm.

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