Question

Find the smallest number which when increased by 13, is exactly divisible by both 344 and 60​

Answer 1

Hey mate here is your answer

Given integers 344 and 60 can be factorised as follows

344=2*2*2*43

60=2*2*3*5

2,3,5,43 are prime numbers as these are the numbers that are only divisible by themselves

The smallest number which when incresed by 13 is exactly divisible by both 344 and 60 is obtained by subtracting 13 from LCM of 344 and 60

LCM of 344 and 60=2*2*2*43*3*5

=5160

Hence the smallest number which when incresed by 13 is exactly divisible by both 544 and 60 is 5160-13=5143

hence the smallest number is 5143

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Answer 2

the number which is exactly divisible by 344 and 60=LCM of 344,60

=2×2×86×15=5160

so,the required number will be 5160-13

=5147