Math, asked by poorabhdanicha, 1 month ago

Find the smallest number which when increased by 15 is divisible by 24, 40 and 90.​

Answers

Answered by shoaibkhan4201122
1

Step-by-step explanation:

Firstly we have To find the LCM of 24,40,90.So it's the LCM of the number by the Method of Prime Factorization is attached in the Above image.

So the correct answer is 360.

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Answered by bobbyrashde
0
345 is the answer. I hope it helped you:)
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