find the smallest number which when increased by 17 is exactly divisible by both 12 &15
Answers
Answered by
0
Answer:
43
Step-by-step explanation:
The smallest number is 43
when it increased by 17 it becomes 60
which is divisible by both 17 and 15
Answered by
0
Answer:
43
Step-by-step explanation:
LCM of 12 and 15 is 60
60 - 17 = 43
so 43 is the smallest no. when increased by 17 is exactly divisible by both 12 and 15.
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