Question

find the smallest number which when increased by 17 is exactly divisible by both 468 and 520

Answer 1

Hey dear here's your answer.......
----------------------------------------------------------------
At first we find the LCM of 468 and 520
= 4680
Now, we subtract 17 from 4680
= 4680-17
= 4663

So, the required number is 4663

........ Hope it helped.......