Question

Find the Smallest Number which when increased by 17 is exactly divisible by both 520 and 468

Answer 1

For this we have to first find their l.c.m . The l.c.m of 520 and 468 is 4680.Then the the smallest number is 4680-17=4663

Answer 2

Let the number be X
1st no. -520
2nd no. -468
Therefore LCM of both number is 4680
Therefore the smallest no. Which when increased by 17 Is divisible by 468 Nd 520 Is 4680 - 17=4663