Math, asked by AARKA33, 7 months ago

Find the smallest number which when increased by 7 is exactly divisible by 6 and 32

Answers

Answered by careenlyngdoh4

3

Step-by-step explanation:

89

Answer. Answer: The smallest number which when increased by 7 is exactly divisible by 6 and 32

Answered by GauravSonwane65

2

Answer:

185

Step-by-step explanation:

32×6=192 & then 192-7=185

means,185+7(increased by 7)

hope it'll help you

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