find the smallest number which when increased by one is excatly divisible by 12,18,24,32,and 40
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3
0 is the smallest number if 1 is added to it it will become 1 and is the common factor
shadowsabers03:
Bro., the question is to find the number which when increased by 1 is
DIVISIBLE by the required numbers.
Not to find the number which when increased by 1 divides the required numbers.
The answer is, find the LCM of the required numbers, then subtract 1.
The answer is 1439.
hlo
Yes,
Answered by
1
it is 0 when it increases it becames 1
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