Math, asked by malli1012, 1 year ago

Find the smallest number which when increased by one is exactly divided by 12,18,24,32and 40

Answers

Answered by 2003omkaar
0

Answer:

48

Step-by-step explanation:


22ericksoncami: Answer is 49
Answered by bobwilson
1

Answer:

4319

Step-by-step explanation:

We are looking for the LCM of 12, 18, 24, 32, and 40

12 - 2 x 2 x 3

18 - 2 x 3 x x3

24 - 2 x 2 x 2 x 3

32 - 2 x 2 x 2 x 2 x 2

40 - 2 x 2 x 2 x 5

2 occurs as a prime factor in 5 of the numbers.

3 occurs as a prime factor in 3 of the numbers.

5 occurs as a prime factor in 1 of the numbers.

2 x 2 x 2 x 2 x 2 x 3 x 3 x 3 x 5 = 4320

since your adding on to this number;

4320 - 1 = 4319

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