find the smallest number which when reduce by 2 becomes divisible by 24 48 64
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The smallest no. divisible by 24,48and64 is the LCM of them which is 1536. now add 2 to it to get 1538 which is the answer.
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Answer:
The smallest number divisible by 24, 48 and 64 is the LCM of them which is 1536. now at 2 to it to get 1538 which is the answer.
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