Find the smallest number wic when divided by 66,77,88 leaves 3 as remainder
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Answered by
5
Answer:
Step-by-step explanation:
Let us find LCM of the numbers.
66=2*3*11.
88=2*2*2*11.
77=7*11
LCM=2*2*2*3*7*11=924
As it has to leave a remainder 3 when divided by these numbers the required number is 924+6=930
930 is the required number.
Answered by
1
Answer:
thanks alot for giving me this answer
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