find the smallest numbers that is divisible by each one of 9,12, and 15
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2
Answer:
3 is the smallest number divisible by 9, 12, and 15.
9/3=3
12/3=4
15/3=5
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Step-by-step explanation:
Write your numbers in a row.
Divide your numbers by prime numbers as long as at least two numbers are evenly divisible by that prime.
Bring down any numbers that are not evenly divisible by the current factor.
When there are no more primes that evenly divide into at least two numbers you are done.
The LCM is the product of the numbers in the L shape, left column and bottom row.
LCM = 3 x 3 x 4 x 5
LCM = 180
Therefore,
LCM(9, 12, 15) = 180
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