Question

Find the smallest positive integer greater than one which yields a remainder of one when divided by any single positive integer greater than 1
. ​

Answer 1

Step-by-step explanation:

Since this number is 1 greater than the number that can be divided by 4, 5, and 6, we have to find the lcm of it. First, let’s find the prime factorizations:

4: 2*2

5: 5

6: 2*3

2*2*3*5 = 60 (Only two 2’s because there is a max of two, like 2*2 is two, and 2 is one, so we take the largest amount, two).

60 + 1 = 61 ANS