Question

find the smallest sq no that is divisible by each of the no 4, 9 and 10​

Answer 1

Answer:

$30^{2}$ = 900

Step-by-step explanation:

Taking L.C.M of 4,9,10 = 2 x 2 x 9 x 5 = 180

so our required square no must divisible by 180 & it should be least as well,

$2^{2}$=4 ( 2 two's)

$3^{2}$=9 ( 2 three's)

2 x 5 = 10 ( 1 five)

required no. = $(2 * 3 * 5)^{2}$ = $30^{2}$ = 900

Answer 2

Step-by-step explanation:

LCM of 4 9 & 10 = 180

180 = (2x2)x9x5, where 9 & 5 can't be paired.

Hence, 180 should be multiplied by 9x5 ie. 45

180x45 = 8100, which is a perfect square

as, √8100 = 90

Hence, the smallest sq no. is 8100.

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