Math, asked by aazi, 1 year ago

Find the smallest square no. Divisible by each one of the nos. 8,9 and 10.

Plzzzzz....... Solve this

Answers

Answered by harini49
1
so let's take the lcm of 8,9 and 10 which is 360.
so when you take lcm you will find that 2and 5 does have pairs. so now you have multiply them which is equal to 10. now multiply the 360 and 10 .you get the answer 3600. check if it is a square number and it is divisible by 8,9 and 10
√3600= 600
3600/8= 450
3600/9=400
3600/10=360
thank you.....
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