Question

Find the smallest square number that is divisible by each of the numbers 8 15 and 20

Answer 1

The number divisible by 8,15,20

= LCM of 8,15,20

8 = 2*2*2

15 = 3*5

20 = 2*2*5

LCM = 2*2*2*3*5*2*2*5

= 2400

The smallest square

= 2400*6

= 11400

Answer 2

Heya mate!!

Step-by-step explanation:

The first number divisible by 8, 15 and 20 will he their L. C. M i.e 120

But on factorising 120 we will find that it's factors are not in pairs, whereas pairin

g is the first rule of finding square or a square root of any number.

Factors of 120 are 2^3*3^1*5^1

Here we see that each prime number needs one more power to become a pair so we increase each of their's exponential powers by one and get 2^4*3^2*5^2

And therefore we conclude that the smallest square number divisible by 8,15 and 20 is 3600, which is the square of 60.

May this help uh!!!