Math, asked by qwertyuiop123456789, 7 months ago

Find the smallest square number that is divisible by each of the numbers 14, 28 and 32.

Answers

Answered by christianShirley23
2

Answer:

3136

Step-by-step explanation:

First Calculate the LCM of 14, 28 and 32.

factors of 14= 2x7

Factors of 28 = 2x2x7

factors of 32 = 2x2x2x2x2

So, LCM = 2x7x2x2x2x2

But, since we want it to be a perfect square

so, we multiply it by 2 and 7 as it will lead us to perfect square.

So, the number is 2x2x2x2x2x2x7x7

49x64

3136

So, the required no. is 3,136.

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