Question

find the smallest square number that is divisible by each of the following number 9 ,6 ,27 36​

Answer 1

the smallest square no. which is divisible by 9 6 27 36 is 3

Answer 2

First, we find the LCM of all these numbers.

LCM = 2 * 2 * 3 * 3 * 3 = 108

All square numbers have pairs of two similar factors in their prime factors

so,

(2 * 2) * (3 * 3) * (3) = 108

Therefore we multiply 108 by 3

(2 * 2) * (3 * 3) * (3 * 3) = 108 * 3 = 324

324 is the answer........