Question

Find the smallest square number that is divisible by each of the numbers 8, 15, and 20.

Answer 1

The number divisible by 8,15,20
= LCM of 8,15,20
8 = 2*2*2
15 = 3*5
20 = 2*2*5

LCM = 2*2*2*3*5*2*2*5
= 2400

The smallest square
= 2400*6
= 11400

Answer 2

Answer:

Answer=2∗2∗2∗2∗3∗3∗5∗5=3600

Step-by-step explanation:

8=2∗2∗2  

15=3∗5

20=2∗2∗5

First find the smallest number divisible by all these 3 numbers i.e the LCM.

LCM=2∗2∗2∗3∗5

Now, since you want a perfect square, you just need to make sure that each prime factor has an even power (occurs in pairs).

For that put in one more 2, one more 3 and one more 5.

Answer=2∗2∗2∗2∗3∗3∗5∗5=3600