Math, asked by shahilraj81, 11 months ago

find the smallest square number that is divisible by each of the number 8 15 and 20​

Answers

Answered by Palak230
15

Answer:

8=2×2×2

15=3×5

20=2×2×5

First find the smallest number divisible by all these 3 numbers i.e the LCM.

LCM=2×2×2×3×5

Now, since you want a perfect square, you just need to make sure that each prime factor has an even power (occurs in pairs).

For that put in one more 2, one more 3 and one more 5.

Answer=2×2×2×2×3×3×5×5=3600.

Hope it helps.....

Answered by simplegirl16
13
Hii dear
here is ur answer
1800 is the smallet number.

Thankyou☺
Attachments:

simplegirl16: I think u r in 8th standard
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