find the smallest square number that is divisible by each of the number 8 15 and 20
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Answered by
15
Answer:
8=2×2×2
15=3×5
20=2×2×5
First find the smallest number divisible by all these 3 numbers i.e the LCM.
LCM=2×2×2×3×5
Now, since you want a perfect square, you just need to make sure that each prime factor has an even power (occurs in pairs).
For that put in one more 2, one more 3 and one more 5.
Answer=2×2×2×2×3×3×5×5=3600.
Hope it helps.....
Answered by
13
Hii dear
here is ur answer
1800 is the smallet number.
Thankyou☺
here is ur answer
1800 is the smallet number.
Thankyou☺
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simplegirl16:
I think u r in 8th standard
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