Question

find the smallest square number that is is divisible by each of the numbers 7 , 28 and 2​

Answer 1

Answer:

• The smallest square number that is is divisible by each of the numbers is 196.

Step-by-step explanation:

Given that:

• Numbers are 7, 28 and 2.

To Find:

• The smallest square number that is is divisible by each of the numbers.

Finding the LCM of these numbers:

By prime factorisation.

• Factors of 7 = 7
• Factors of 28 = 2² × 7
• Factors of 2 = 2

LCM of 7, 28 and 2 = (2² × 7) = 28

Checking 28 is a perfect square or not:

By prime factorisation.

• Factors of 28 = 2 × 2 × 7

7 is not in pair so it is not a perfect square if we multiply with 7 then it will be perfect square.

Multiplying with 7.

• 28 × 7 = 196

Hence,

• The smallest square number that is is divisible by each of the numbers is 196.

Answer 2

✯ Question:-

Find the smallest square number that is divisible by each of the numbers 7, 28, and 2.

✯ Answer:-

• 196

✯ Process:-

◍ Given:-

• The three numbers 7, 28, 2

◍ To Find:-

• Smallest number that can be divisible by the given three numbers.

◍ Solution:-

=> Step 1:-

Finding the LCM of the three numbers:-

• Method:-

Prime Factorisation:-

• Factors of 7 = 7
• Factors of 28 = 2 × 2 × 7 or 2² × 7
• Factors of 2 = 2

So,

The LCM of 7, 28 and 2 = 28

=> Step 2:-

Verifying if 28 is a perfect square:-

• The factors of 28 = 2 × 2 × 7

Here we get to know that 7 isn't a pair.

Hence,

We must multiply 7 to 28

= 28 × 7 = 196

Therefore,

196 is the smallest square number that can be divisible by all the three numbers in the question.

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