Question

find the smallest square number that it is divisible by each of the number 8,15 and 20​

Answer 1

Step-by-step explanation:

The number that is perfectly divisible by each of the numbers 8, 15, and 20 is their LCM. Here, prime factors 2, 3, and 5 do not have their respective pairs. Therefore, 120 is not a perfect square. Therefore, 120 should be multiplied by 2 × 3 × 5, i.e. 30, to obtain a perfect square.

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Answer 2

Smallest square number is 3600.

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Find the smallest square number that it is divisible by each of the number 8,15 and 20?

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Given:-

• Numbers: = 8,15 and 20

Find:-

• Smallest number which is divisible by each number.

Before finding the square number, first we have to find LCM of these numbers.

LCM of 8, 15 and 20 = 2×2×2×3×5

• = 4×6×5
• = 120

Checking if 120 is perfect square or not.

120 = 2×2×2×3×5

• Here, 2 , 3 and 5 doesn't occur in pair.
• So ,we have to make pair of 2,3 and 5.

Therefore, our numbers will become:-

120 = 2×2×2×2×3×3×5×5

Now this number will becomes perfect square,

= 2×2×2×2×3×3×5×5

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Therefore, the smallest number is 3,600.