find the smallest square number which is completely divisible by each of the numbers 10 ,16 and 24
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3600
Step-by-step explanation:
10 = 5 × 2
16 = 2 × 2 × 2 × 2
24 = 2 × 2 × 2 × 3
Smallest number divisible by 10 , 16 and 24 is
N = 2 × 2 × 2 × 2 × 3 × 5
But N is not a perfect square because 3 and 5 are present in N in odd powers.
Minimum N = 2 × 2 × 2 × 2 × 3 × 3 × 5 × 5 = 3600
The minimum required N is 3600
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